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A battery of emf 6 V and negligible inte...

A battery of emf 6 V and negligible internal resistance is connected to the terminals of a potentiometer wire of length 4 m. The wire is of uniform cross-section and its resistance is 100 `Omega` . The difference of potential between two points separated by 40 cm on the wire will be

A

0.4 V

B

0.6 V

C

1.0 V

D

2V

Text Solution

Verified by Experts

The correct Answer is:
B
`V = (epsi l)/(L) = (6 xx (40 cm))/((4m)) = (6 xx (40 cm))/((400 cm)) = 0.6 V`
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