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If both the length and radius of a metal...

If both the length and radius of a metallic wire are doubled then its resistance remains unchanged.

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False - In length and radius both are doubled then l. = 2l and A. = 4A and hence resistance
`R. = (rho l.)/(A.) = (rho (2l))/((4A)) = 1/2 (rhol)/(A) = R/2`
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