Home
Class 12
PHYSICS
A battery of 6 volts is connected to the...

A battery of 6 volts is connected to the terminals of 3 m long wire of uniform thickness and resistance Fig. of the order of 60 `Omega`. The difference of potential between two points separated by 50 cm on the wire will be

A

1V

B

1.5V

C

2V

D

3V

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    U-LIKE SERIES|Exercise SELF ASSESSMENT TEST (SECTION A (FILL IN THE BLANKS))|2 Videos

  • CURRENT ELECTRICITY

    U-LIKE SERIES|Exercise SELF ASSESSMENT TEST (SECTION C )|3 Videos

  • CURRENT ELECTRICITY

    U-LIKE SERIES|Exercise LONG ANSWER QUESTIONS - II|8 Videos

  • CBSE SAMPLE QUESTION PAPER 2019-20 (SOLVED)

    U-LIKE SERIES|Exercise SECTION D|6 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    U-LIKE SERIES|Exercise SELF ASSESSMENT TEST SECTION-C (VERY SHORT ANSWER QUESTIONS)|3 Videos

Similar Questions

Explore conceptually related problems

A battery of 6 volts is connected ot the termainals of a three meter long wire of uniform thickness and resistance of the order of 100 Omega . The difference of potential between two points separated by 50 cm on the wire will

A 6 V battery is connected to the terminals of a 3 m long wire of uniform thickness and resistance of 100 Omega . The difference of potential between two points on the wire separated by a distance of 50 cm will be

A 6 V battery is connected to the terminal of a 3 m long wire of uniform thickness and resistance of 100 Omega along with another 100 Omega resistor in series . The difference of potentials between two points on the wire separated by a distance of 50 cm will be

A cell of emf 2 volt and internal resistance 1.5 Omega is connected to the ends of 1 m long wire. The resistance of wire is 0.5 Omega/m . Find the value of potential gradient on the wire.

A cell of emf 2 volt and internal resistance 1.5Omega is connected to the ends of 1 long wire. The resistance of wire is (0.5Omega)/(m) . Find the value of potential gradient on the wire.

In an uniform electric field,the potential difference between two points separated by 10cm is 2 volt.Magnitude of electric field .

The resistance of a 50 cm long wire is 10 Omega . The wire is stretched of uniform wire of length 100 cm. The resistance now will be

A thin uniform wire AB of length 50 cm and resistance 1 Omega is connected to be terminals of a battery of emf epsilon_(1) = 2.2 V and internal resistance 0.1 Omega . If the terminals of another cell (assume ideal) are connected to two points 25 cm apart on the wire AB without altering the current in the wire AB, the emf epsilon_(2) of cell in volts is :