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Show that the progression 7,12,17,22,27...

Show that the progression `7,12,17,22,27, ….,` is an AP. Find its general term and the `14^(th)` term.

Text Solution

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we have
(12-7) = ( 17-12) = ( 22 -17) = ( 27-22) = 5, which is contant .
So , the given progression is an AP in which a=78 and d =5
Its general term, ` T_(n) = ( a+ (n-d)d}= 7 + ( n -1) xx 5 Rightarrow T_(n) = ( 5n +2)`
14th term , ` T_(14) = ( 5xx 14 +2) =72`
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