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Show that the term independent of x in the expansion of `(x-1/x)^(10) is -252`.

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To find the term independent of \( x \) in the expansion of \( (x - \frac{1}{x})^{10} \), we can use the Binomial Theorem. The Binomial Theorem states that: \[ (a + b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r \] In our case, we have \( a = x \) and \( b = -\frac{1}{x} \), and \( n = 10 \). Therefore, the expansion is: ...
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Knowledge Check

  • The term independent of x in the expansion of (2x+1/(3x))^(6) is

    A
    160/9
    B
    80/9
    C
    160/27
    D
    80/3
  • The term independent of x in the expansion of (x-3/x^(2))^(18) is

    A
    `.^(18)c_(6)0`
    B
    `.^(18)c_(6)3^(6)`
    C
    `.^(18)c_(12)`
    D
    `.^(18)c_(6)3^(12)`
  • The term independent of x in the expansion of ( x - (1)/(x) )^(12) is

    A
    924
    B
    462
    C
    231
    D
    693
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