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A bullet is fired from a gun. The force ...

A bullet is fired from a gun. The force on the bullet is given by `F=600-2xx10^(5)` t, where F is in newtons and t in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet?

A

9 N-s

B

zero

C

1.8 N-s

D

0.9 N-s

Text Solution

Verified by Experts

The correct Answer is:
D
When F =0
`600 -2 xx 10^(5) t =0 rArr t = 600/(2 xx 10^(5)) = 3 xx 10^(-3) s`
Now, impulse, `I = int_(0)^(t) F dt = int_(0)^(t) (600 - 2 xx 10^(5) t) dt`
`I = 600 t - 2 xx 10^(5) (t^(2)/2) =600 xx 3 xx 10^(-3) xx (3 xx 10^(-3))^(2)` or I = 0.9 N-s.
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