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From the top of a tower, 80m high from t...

From the top of a tower, 80m high from the ground a stone is thrown in the horizontal direction with a velocity of `8 ms^(1)`. The stone reaches the ground after a time t and falls at a distance of d from the foot of the tower. Assuming `g=10ms^(2)`, the time t and distance d are given respectively by

A

6s, 64 m

B

6s, 48 m

C

4s, 32 m

D

4s, 16 m

Text Solution

Verified by Experts

The correct Answer is:
C
Here, `u = 8 ms^(-1), h= 80 m`

The time taqen by the stone to reach the ground is
`t = sqrt((2h)/g) = sqrt((2 xx 80 m)/(10 ms^(-2))) = 4s`
Distance `d = u xx t = 8 ms^(-1) xx 4s = 32 m`
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