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What is int e^("In"(tan x)) dx equal to ...

What is `int e^("In"(tan x)) dx` equal to ?

A

In `|tan x| + c`

B

In `|sec x| + c`

C

`tan x + c`

D

`e^(tan x) + c`

Text Solution

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The correct Answer is:
To solve the integral \( \int e^{\ln(\tan x)} \, dx \), we can follow these steps: ### Step 1: Simplify the integrand Using the property of exponents and logarithms, we know that \( e^{\ln(a)} = a \). Therefore, we can simplify the integrand: \[ e^{\ln(\tan x)} = \tan x \] ### Step 2: Set up the integral Now we can rewrite the integral: \[ \int e^{\ln(\tan x)} \, dx = \int \tan x \, dx \] ### Step 3: Integrate \( \tan x \) The integral of \( \tan x \) can be computed using the identity: \[ \tan x = \frac{\sin x}{\cos x} \] Thus, we can use the substitution method or recognize the integral directly. The integral of \( \tan x \) is: \[ \int \tan x \, dx = -\ln|\cos x| + C \] ### Step 4: Rewrite the result Using the property of logarithms, we can rewrite \( -\ln|\cos x| \) as: \[ \int \tan x \, dx = \ln|\sec x| + C \] ### Final Answer Thus, the final result of the integral is: \[ \int e^{\ln(\tan x)} \, dx = \ln|\sec x| + C \]

To solve the integral \( \int e^{\ln(\tan x)} \, dx \), we can follow these steps: ### Step 1: Simplify the integrand Using the property of exponents and logarithms, we know that \( e^{\ln(a)} = a \). Therefore, we can simplify the integrand: \[ e^{\ln(\tan x)} = \tan x \] ...
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