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If alpha is a non-real cube root of -2, ...

If `alpha` is a non-real cube root of `-2`, then the value of `|(1,2 alpha,1),(alpha^(2),1,3 alpha^(2)),(2,2 alpha,1)|`, is

A

`-11`

B

`-12`

C

`-13`

D

0

Text Solution

Verified by Experts

The correct Answer is:
C

We have, `alpha = (-2)^(1//3) w or , alpha = (-2)^(1//3) w^(2)`
`:. alpha^(3) = -2`
Now, `|(1,2 alpha,1),(alpha^(2),1,3 alpha^(2)),(2,2 alpha,1)|`
`= |(1,2 alpha,1),(alpha^(2),1,3 alpha^(2)),(1,0,0)| " " ["Applying" R_(3) rarr R_(3) - R_(1)]`
`= 6alpha^(3) - 1` [On expanding along `R_(3)`]
`= -13 " " [ :' alpha^(3) = -2]`
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