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If {:[(a,b^3),(2,0)]=[(1,8),(2,0)]," th...

If `{:[(a,b^3),(2,0)]=[(1,8),(2,0)]," then " [(a,b),(2,0)]_(-1)^1:}=`

A

`{:[(0,-2),(-2,1)]:}`

B

`{:[(1,0),(0,1)]:}`

C

`{:[(0,-8),(-2,1)]:}`

D

`{:[(0,1//2),(1//2,-1//4)]:}`

Text Solution

Verified by Experts

The correct Answer is:
D

We have,
`{:[(a,b^3),(2,0)]=[(1,8),(2,0)]:}rArr a=1,b^3=8rArra=1,b=2`
`:. {:[(a,b),(2,0)]=[(1,2),(2,0)]:}`
Hence,`{:[(a,b),(2,0)]^(-1)=-1/4[(0,-2),(-2,1)]=[(0,1//2),(1//2,-1//4)]:}`
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OBJECTIVE RD SHARMA-MATRICES-Section I - Solved Mcqs
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  2. A square matrix can always be expressed as

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  8. If A^(3)=O, then prove that (I-A)^(-1) =I+A+A^(2).

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