Let f(x)=x/((1+x^n)^(1/ n)) for ngeq2 a...

Let `f(x)=x/((1+x^n)^(1/ n))` for `ngeq2` and `g(x)=(f(ofo ...of)(x)` Then `intx^(n-2)g(x)dx` equals

`(1)/(n(n-1))(1+nx^(n))^(1-(1)/(n))+k`

`(1)/(n-1)(1+nx^(n))^(1-(1)/(n))+k`

`(1)/(n(n-1))(1+nx^(n))^(1+(1)/(n))+k`

`(1)/(n-1)(1+nx^(n))^(1+(1)/(n))+k`

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