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The range of the function f(x) = log(3) ...

The range of the function `f(x) = log_(3) (5+4x - x^(2))`, is

A

`(0, 2 ]`

B

`(-oo, 2]`

C

`(0, 9]`

D

none of these

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The correct Answer is:
To find the range of the function \( f(x) = \log_{3}(5 + 4x - x^{2}) \), we will follow these steps: ### Step 1: Identify the expression inside the logarithm We need to analyze the expression \( 5 + 4x - x^{2} \). This is a quadratic function, and we can rewrite it in standard form: \[ f(x) = -x^{2} + 4x + 5 \] ### Step 2: Determine the nature of the quadratic The coefficient of \( x^{2} \) is negative, which indicates that the parabola opens downwards. This means it has a maximum point. ### Step 3: Find the vertex of the quadratic To find the maximum value, we can use the vertex formula for a quadratic \( ax^{2} + bx + c \), where the x-coordinate of the vertex is given by: \[ x = -\frac{b}{2a} \] Here, \( a = -1 \) and \( b = 4 \): \[ x = -\frac{4}{2 \times -1} = 2 \] ### Step 4: Calculate the maximum value of the quadratic Now, we substitute \( x = 2 \) back into the quadratic to find the maximum value: \[ f(2) = 5 + 4(2) - (2)^{2} = 5 + 8 - 4 = 9 \] ### Step 5: Determine the minimum value of the quadratic Next, we need to find the values of \( x \) for which \( 5 + 4x - x^{2} > 0 \): \[ 5 + 4x - x^{2} = 0 \] Rearranging gives: \[ -x^{2} + 4x + 5 = 0 \] Using the quadratic formula \( x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a} \): Here, \( a = -1, b = 4, c = 5 \): \[ x = \frac{-4 \pm \sqrt{4^{2} - 4(-1)(5)}}{2(-1)} = \frac{-4 \pm \sqrt{16 + 20}}{-2} = \frac{-4 \pm \sqrt{36}}{-2} \] \[ = \frac{-4 \pm 6}{-2} \] Calculating the two roots: 1. \( x = \frac{2}{-2} = -1 \) 2. \( x = \frac{-10}{-2} = 5 \) Thus, the quadratic \( 5 + 4x - x^{2} \) is positive between the roots \( x = -1 \) and \( x = 5 \). ### Step 6: Determine the range of \( f(x) \) Since \( 5 + 4x - x^{2} \) is positive in the interval \( (-1, 5) \), the logarithmic function \( f(x) \) will take values from \( \log_{3}(0) \) (which approaches \(-\infty\)) to \( \log_{3}(9) \) (which is \( 2 \)): \[ \text{Range of } f(x) = (-\infty, 2) \] ### Final Answer The range of the function \( f(x) = \log_{3}(5 + 4x - x^{2}) \) is \( (-\infty, 2) \). ---

To find the range of the function \( f(x) = \log_{3}(5 + 4x - x^{2}) \), we will follow these steps: ### Step 1: Identify the expression inside the logarithm We need to analyze the expression \( 5 + 4x - x^{2} \). This is a quadratic function, and we can rewrite it in standard form: \[ f(x) = -x^{2} + 4x + 5 \] ...
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