Ramesh solved `2/7` part of an exercise while Seema solved `4/5` of it. Who solved lesser part?

Options

A. Seema
B. Ramesh
C. Both solved equal parts
D. Can not be decided

Explanation

To determine who solved the lesser part of the exercise between Ramesh and Seema, we need to compare the fractions \( \frac{2}{7} \) and \( \frac{4}{5} \). Here’s a step-by-step solution:

### Step 1: Identify the fractions
Ramesh solved \( \frac{2}{7} \) of the exercise, and Seema solved \( \frac{4}{5} \).

### Step 2: Find a common denominator
To compare the two fractions, we need to have a common denominator. The denominators are 7 and 5. We can find the least common multiple (LCM) of these two numbers.

- The LCM of 7 and 5 is \( 7 \times 5 = 35 \).

### Step 3: Convert the fractions to have the same denominator
Now, we will convert both fractions to have the common denominator of 35.

- For Ramesh's fraction \( \frac{2}{7} \):
\[ \frac{2}{7} = \frac{2 \times 5}{7 \times 5} = \frac{10}{35} \]

- For Seema's fraction \( \frac{4}{5} \):
\[ \frac{4}{5} = \frac{4 \times 7}{5 \times 7} = \frac{28}{35} \]

### Step 4: Compare the fractions
Now that both fractions have the same denominator, we can compare them directly:

- Ramesh's solved part: \( \frac{10}{35} \)
- Seema's solved part: \( \frac{28}{35} \)

Since \( 10 < 28 \), we can conclude that:

\[ \frac{10}{35} < \frac{28}{35} \]

### Step 5: Conclusion
Thus, Ramesh solved the lesser part of the exercise.

### Final Answer
Ramesh solved the lesser part.

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