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Magnetic intensity for an axial point du...

Magnetic intensity for an axial point due to a short bar magnet of magnetic moment `M` is given by

A

`(mu_(0))/(4pi) xx (M)/(d^(3))`

B

`(mu_(0))/(4pi) xx (M)/(d^(2))`

C

`(mu_(0))/(2pi) xx (M)/(d^(3))`

D

`(mu_(0))/(2pi) xx (M)/(d^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • The magnetic induction at any point due to a short magnetic dipole is

    A
    `(pi_(0))/(4pi)(M)/(r^(3))sqrt(3cos^(2)theta+1)`
    B
    `(pi_(0))/(4pi) (2M)/(r^(2))sqrt(3cos^(2)theta+1)`
    C
    `(pi_(0))/(4pi)sqrt(3cos^(2)theta+1)`
    D
    `(pi_(0))/(4pi)(2M)/(r^(3)sqrt(3cos^(2)theta+1))`

  • The magnetic field strength at a point a distance 'd' form the centre on the axial line of a very short bar magnet of magnetic moment 'M' is 'B' . Then magnetic induction at a diatance 2d from the centre on the equatorial line of a magnetic moment 8M will be

    A
    `4B`
    B
    `B//2`
    C
    `B//4`
    D
    `2B`

  • What is the magnetic induction due to a short bar magnet of magnetic moment 0.5 Am^(2) at a point along the equator at a distance of 20 cm from the centre of the magnet?

    A
    `12.5xx10^(-6)" Wb/m"^(2)`
    B
    `6.25xx10^(-6)" Wb/m"^(2)`
    C
    `3.5xx10^(-6)" Wb/m"^(2)`
    D
    `18.5xx10^(-6)" Wb/m"^(2)`

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    The magnetic potential at a point on the axial line of a bar magnet of dipole moment M is V . What is the magnetic potential due to a bar magnet of dipole moment M/4 at the same point ?

    The ratio of magnitude of magnetic induction (B)at any point due to short magnetic dipole and the magnetic potential (V) at that point is given by

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