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What acn be the largest distance of an i...

What acn be the largest distance of an image of a real object from a convex mirror of radius of curvature 20 cm

A

10 cm

B

Infinity

C

20 cm

D

None

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The correct Answer is:
To solve the problem of finding the largest distance of an image of a real object from a convex mirror with a radius of curvature of 20 cm, we can follow these steps: ### Step 1: Understand the relationship between radius of curvature and focal length The focal length (f) of a convex mirror is given by the formula: \[ f = \frac{R}{2} \] where R is the radius of curvature. Given that R = 20 cm, we can calculate f: \[ f = \frac{20 \, \text{cm}}{2} = 10 \, \text{cm} \] **Hint:** Remember that for convex mirrors, the focal length is positive and is half of the radius of curvature. ### Step 2: Use the mirror formula The mirror formula for curved mirrors is: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] where: - \( f \) is the focal length, - \( v \) is the image distance, - \( u \) is the object distance (which is negative for real objects in the case of mirrors). ### Step 3: Substitute the known values into the mirror formula Since we know \( f = 10 \, \text{cm} \), we can rewrite the formula: \[ \frac{1}{10} = \frac{1}{v} + \frac{1}{u} \] ### Step 4: Express \( u \) in terms of \( v \) Rearranging the formula gives: \[ \frac{1}{v} = \frac{1}{10} - \frac{1}{u} \] This can be rewritten as: \[ \frac{1}{v} = \frac{u - 10}{10u} \] Thus, \[ v = \frac{10u}{u - 10} \] ### Step 5: Find the maximum value of \( v \) To find the maximum value of \( v \), we can differentiate \( v \) with respect to \( u \) and set the derivative to zero: Let: \[ v = \frac{10u}{u - 10} \] Differentiating \( v \) with respect to \( u \): \[ \frac{dv}{du} = \frac{(u - 10)(10) - 10u(1)}{(u - 10)^2} = \frac{10u - 100}{(u - 10)^2} \] Setting the numerator to zero for maximum: \[ 10u - 100 = 0 \] \[ u = 10 \, \text{cm} \] ### Step 6: Substitute \( u \) back to find \( v \) Substituting \( u = 10 \, \text{cm} \) back into the equation for \( v \): \[ v = \frac{10(10)}{10 - 10} \] As \( u \) approaches infinity, \( v \) approaches the focal length: \[ v \to 10 \, \text{cm} \] ### Conclusion The largest distance of the image from the convex mirror is 10 cm. **Final Answer:** The largest distance of an image of a real object from a convex mirror of radius of curvature 20 cm is 10 cm. ---
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