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A man stands in front of a large vertica...

A man stands in front of a large vertical plane mirror.His height is 1.8 m. The distance of image from the man is 4 m. At what distance is the man standing from the mirror?

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The correct Answer is:
To solve the problem step by step, we can follow this reasoning: ### Step 1: Understand the relationship between the object and the image in a plane mirror. In a plane mirror, the distance of the image from the mirror is equal to the distance of the object (the man) from the mirror. If the man is standing at a distance \( x \) from the mirror, then the image will also be at a distance \( x \) behind the mirror. ### Step 2: Set up the equation based on the given information. We know that the distance between the man and his image is given as 4 meters. Since the image is behind the mirror, the total distance between the man and the image can be expressed as: \[ \text{Distance between man and image} = \text{Distance from man to mirror} + \text{Distance from mirror to image} \] This can be written as: \[ 4 \text{ m} = x + x \] where \( x \) is the distance from the man to the mirror. ### Step 3: Simplify the equation. From the equation above, we can simplify it: \[ 4 \text{ m} = 2x \] ### Step 4: Solve for \( x \). To find \( x \), we divide both sides of the equation by 2: \[ x = \frac{4 \text{ m}}{2} = 2 \text{ m} \] ### Step 5: State the final answer. Thus, the distance at which the man is standing from the mirror is: \[ \text{Distance from the man to the mirror} = 2 \text{ m} \] ### Summary of the Solution: The man is standing 2 meters away from the mirror. ---
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