In an old-fashioned television set, electrons are accelerated through a potential difference of 25.0 kV. What is the de Broglie wavelength of such electrons? (Relativity is not needed.)

Explanation

To find the de Broglie wavelength of electrons accelerated through a potential difference of 25.0 kV, we can follow these steps:

### Step 1: Understand the relationship for de Broglie wavelength
The de Broglie wavelength (\(\lambda\)) is given by the formula:
\[ \lambda = \frac{h}{p} \]
where \(h\) is Planck's constant and \(p\) is the momentum of the particle.
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