The smallest dimension (resolving power) that can be resolved by an electron microscope is equal to the de Broglie wavelength of its electrons. What accelerating voltage would be required for the electrons to have the same resolving power as could be obtained using 120 keV gamma rays?

Explanation

To find the accelerating voltage required for electrons to have the same resolving power as 120 keV gamma rays, we will follow these steps:

### Step 1: Understand the relationship between wavelength and energy
The resolving power of an electron microscope is determined by the de Broglie wavelength of the electrons, which can be expressed as:
\[ \lambda = \frac{h}{p} \]
where \( h \) is Planck's constant and \( p \) is the momentum of the electrons.
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