An atom (not a hydrogen atom) absorbs a photon whose associated frequency is `5.6x x 10^(14)` Hz. By what amount does the energy of the atom increase?

Explanation

To find the increase in energy of an atom that absorbs a photon, we can use the formula for the energy of a photon, which is given by:

\[ E = h \cdot f \]

where:
- \( E \) is the energy of the photon,
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{Js} \)),
- \( f \) is the frequency of the photon.
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