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The distance between two successive node...

The distance between two successive nodes in a stationary wave is 30 cm. Calculate the frequency of wave if its speed is 250 m/s.

Text Solution

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Distance between two successive nodes `= lambda//2`
Given, 30 cm `= lambda//2`
`therefore" "lambda = 60 cm = 0.60 m`
`upsilon = 250` m/s
`therefore` Frequency, `v = (upsilon)/(lambda) = (250)/(0.60) = 416.67` Hz
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