The displacement of an elastic wave is given by the function `y=3 sin omega t +4 cos omegat .`
where y is in cm and t is in second. Calculate the resultant amplitude.

Explanation

Given `y = 3 sin omega t + 4 cos omega t`
`y = 3 sin omega t + 4 sin (omega t + (pi)/(2))`
Here we have two amplitudes 3 cm and 4 cm and phase `phi = 90^(@)`.
So resultant amplitude
`= sqrt(3^(2) + 4^(2) + 2 xx 3 xx 4 cos 90^(@))`
`= sqrt(9 + 16 + 0) = sqrt(25) = 5` cm