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A battery of negligile internal resistance connected in a circuit is maintaining a current of 5 A and it is found that battery does a work of 800 J in an interval of 2 minutes. What is the emf of the battery ?

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Current I= 5A
Time, t=2min `=2 xx 60= 120s`
Charge, q= It `=5 xx 120=600C`
Work done, W=800J
emf of the battery, `E= (W)/(q) = (800)/(600)= 1.33V`
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