A galvanometer shows full scale deflection when a current of 1 mA is passed through it . The resistance of the coil used in galvanometer is `100 Omega` How will you convert it into an ammeter which should be able to measure the current up to 5 A ?

Explanation

To convert a galvanometer into an ammeter that can measure up to 5 A, we can follow these steps:

### Step 1: Understand the given values
- Full scale deflection current of the galvanometer, \( I_g = 1 \, \text{mA} = 0.001 \, \text{A} \)
- Resistance of the galvanometer, \( R_g = 100 \, \Omega \)
- Desired maximum current for the ammeter, \( I = 5 \, \text{A} \)

### Step 2: Determine the shunt resistance needed
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