A galvanometer shows full-scale deflection when current of 1 mA is passed through it. Resistance of the coil used in the galvanometer is `100 Omega` what maximum potential difference can be measured if it is used as a voltmeter ? How will you modify it to measure potential difference up to 2 V ?

Explanation

To solve the problem, we need to determine the maximum potential difference that a galvanometer can measure and how to modify it to measure a higher potential difference.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Full-scale deflection current of the galvanometer (\(I_G\)) = 1 mA = \(1 \times 10^{-3}\) A
- Resistance of the galvanometer (\(R_G\)) = 100 Ω

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