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At room temperature (27.0^@C) the resist...

At room temperature `(27.0^@C)` the resistance of a heating element is `100 Omega`. What is the temperature of the element if the resistance is found to be `117 Omega`, given that the temperature coefficient of the material of the resistor is `1.70 xx 10^(-4) .^@C^(-1)`.

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`1,027^@C` (if use (ii))
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At room temperature (27.0^@C) the resistance of a heating element is 100 Omega . What is the temperature of the element if the resistane is found to be 117 Omega , given that the temperature co-efficicent of the material of the resistor is 1.70 xx 10^(-4) .^@C^(-1) .

At room temperature (27^@C) the resistance of a heating element is 100 Omega. Wheat is the temperature of the element is the resistace is found to 117Omega? Given that the teperature coefficint of the meterail of the resistor is 1.70xx10^(-40) C^(-1)

At room temperature (27^(@)C) , the resistance of a heating element is 100 Omega . What is the temperature of the element if the resistance is found to be 117 Omega , given that temperature coefficient of the resistor material is 1.70xx10^(-4) .^(@)C^(-1) .

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The resistance of a platinum wire is 15 Omega at 20^(@)C . This wire is put in hot furnace and lthe resistance of the wire is found to be 40 Omega . Find the temperature of the hot furnace if temperature coefficient of resistance of platinum is 3.6 xx 10^(-3)^(0)C^(-1)

At what temperature(in kelvin) would the resistance of a copper wire be half its resistance at 0^@C ? Temperature coefficient of resistance of copper is 3.9 xx 10^(-3).^(@)C^(-1) .

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The resistance of a wire at room temperature 30^(@)C is found to be 10 Omega . Now to increase the resistance by 10% , the temperature of the wire must be [ The temperature coefficient of resistance of the material of the wire is 0.002 per .^(@)C ]

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