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Two cells of 1.5 V and 2 V , having int...

Two cells of 1.5 V and 2 V , having internal resistances of `1Omega` and `2Omega` respectively, are connected in parallel so as to read the current in the same direction through an external resistance of `5 Omega` . The current in the external resistance will be

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`0.29 Omega`
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MODERN PUBLICATION-CURRENT ELECTRICITY-PRACTICE PROBLEMS
  1. Arrange six identical cells of emf 2 V and internal resistance 0.5 Ome...

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  2. Arrange 32 identical cells of emf 2 V each with internal resistance 0....

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  3. Calculate the current passing through each resistor in the given circu...

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  4. Use the kirchhoff's rule to calculate the current through each resist...

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  5. A cell of emf epsilon and internal resistance r is connected across a ...

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  6. Two cells of 5 V and 10 V and internal resistances 0.8 Omega and 1.2 O...

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  7. Three identical cells each of 2 V and unknow internal resistance are c...

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  8. Two cells of 1.5 V and 2 V , having internal resistances of 1Omega an...

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  9. Three cells of emfs varepsilon1=1.5 V, varepsilon2=2.0 v and varepsilo...

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  10. Twelve identical resistances of resistance 2 Omega are connected in a ...

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  11. Twelve identical wires of resistance 2 Omega are connected in a form o...

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  12. Five resistors are connected as shown in the figure. Find the net resi...

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  13. Three identical resistors of resistance 12 Omega are connected with a ...

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  14. In the metre bridge shown in adjoining figure , the null point is foun...

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  15. Two unknown resistors X and Y are connected in the left and right gaps...

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  16. A voltmeter of resistance 998 Omega is connected across a cell of emf ...

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  17. When a current of 5 mA is passed through a galvanometer of resistance ...

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  18. In the previous problem, the galvanometer is converted to an ammeter, ...

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  19. Calculate the potential gradient of a potentiometer wire of length 5 m...

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  20. A resistance of X is connected to a potentiometer of resistance R and ...

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