Two cells of emfs `epsilon_(1)and epsilon_(2)` and internal resistances `r_(1)and r_(2)` respectively are connected in parallel . Obtain expressions for the equivalent (i) resistance and , (ii) emf of the combination.

Two batteris of emf epsilon_(1) and epsilon_(2) wit respective internal resistance r_(1) and r_(2) are connected in parallel. Now

Two batteries of emf epsi_(1) and epsi_(2)(epsi_(2) gt epsi_(1)) and internal resistance r_(1) and r_(2) respectively are connected in parallel as shown in figure.

Two batteries of emf epsilon_(1) and epsilon_(2) (epsilon_(2)gtepsilon_(1) and internal resistances r_(1) and r_(2) respectively are connected in parallel as shown in Fig. 2 (EP).1.

Two batteries of e.m.f. E_(1) and E_(2) and internal resistance r_(1) and r_(2) are connected in parallel. Determine their equivelent e.m.f.

A parallel combination of two cells of emfs epsilon_(1) and epsilon_(2) , and internal resistance r_(1) and r_(2) is used to supply current to a load of resistance R. Write the expression for the current through the load in terms of epsilon_(1), epsilon_(2),r_(1) and r_(2) .