One kg of water, at `20^(@)C`, is heated in an electric kettle whose heating element has a mean (temperature averaged) resistance of `20 Omega`. The rms voltage in the mains is 200V. Ignoring heat loss from the kettle, time taken for water to evaporate fully, is close to: [specific heat of water= 4200J/kg `""^(@)C`], Latent heat of water = 2260kJ/kgI

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the heat required to raise the temperature of water from 20°C to 100°C.

The formula for heat required to change the temperature is given by:
\[ Q_1 = mc\Delta T \]
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