Calculate the molarity of pure water (d=1 g/mL).

Explanation

Density of water ` = 1 g mL^(-1)`
Mass of 1000 mL of water `= "Volume" xx "Density"`
` = 1000 xx 1 = 1000 g`
Moles of water ` = (1000)/(18) = 55.55 mol`
Now , 55.55 moles of `H_(2)O` are present in 1000 ml or 1L of water .
`therefore ` Molarity = 55.55 M.