A sugar syrup of weight `214.2 g` contains `34.2 g` of sugar `(C_(12) H_(22) O_(11))`. Calculate
a. the molal concentration.
b. the mole fraction of the sugar in the syrup.

Explanation

(i) Weight of sugar syrup = 214.2
Weight of sugar in syrup = 34.2 g
Weight of water in syrup = 214.2 - 34.2 = 180.0 g
Moles of sugar ` = (34.2)/(342) = 0.1` (molar mass = 342)
Molaltiy ` = (0.1)/(180) xx 1000 = 0.56 m`
(ii) Moles of sugar ` = (34.2)/(342) = 0 .1`
Moles of water ` = (180)/(18) = 10`
Moles of water `= (180)/(18) = 10`
Mole fraction of sugar ` = (0.1)/(10+0.1) = 0.0099`