The vapour pressure of ethyl alcohol at 298 K is 40 mm of Hg. Its mole fraction in a solution with methyl alcohol is 0.80. What its vapour pressure in solution if the mixture obeys Raoult's law ?

Explanation

To find the vapor pressure of ethyl alcohol in a solution with methyl alcohol, we can use Raoult's law, which states that the vapor pressure of a component in a solution is equal to the vapor pressure of the pure component multiplied by its mole fraction in the solution.

### Step-by-Step Solution:

1. **Identify the given values:**
- Vapor pressure of pure ethyl alcohol (P₀) = 40 mmHg
- Mole fraction of ethyl alcohol (X₁) = 0.80

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