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A solution prepared by dissolving 1.25g ...

A solution prepared by dissolving `1.25g` of oil of winter green (methyl sallicylate) in `99.0g` of benzene has a boiling point of `80.31^(@)C`. Determine the molar mass of this compound. (`B.P.` of pure benzene `=80.10^(@)C` and `K_(b)` for benzene `=2.53^(@)C kg "mol".1`)

Text Solution

Verified by Experts

`Delta T_(b) = (k_(b) xx 1000 xx w_(B))/(M_(B) xx w_(A))`
or `" " M_(B) = (k_(b) xx 1000 xx w_(B))/(Delta T_(b) xx w_(A))`
`k_(b) = 2.53^(@)C Kg mol^(-1)`
`w_(A) = 99.0 g , w_(B) = 1.25 g`
` Delta T_(b) = 80.31 - 80.10 = 0.21^(@)C`
`M_(B) = (2.53 xx 1000 xx 1.25)/(0.21 xx 99.0)`
` = 1521 g mol^(-1)`
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