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A solution containing 15 g urea ( molar ...

A solution containing 15 g urea ( molar mass = `60 g mol^(-1)`) per litre of solution in water has the same osmotic pressure (isotonic) as a solution of glucose (molar mass = 180 ` g mol^(-1)`) in water . Calculate the mass of glucose persent in one litre of its solution.

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To solve the problem, we need to calculate the mass of glucose present in one liter of its solution, given that it has the same osmotic pressure as a solution containing 15 g of urea per liter. ### Step-by-Step Solution: 1. **Identify the Given Information:** - Mass of urea = 15 g - Molar mass of urea = 60 g/mol - Molar mass of glucose = 180 g/mol ...
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(a) Define the following terms: (i) Molarity (ii) Molal elevation constant (k_(b)) (b) A solution containing 15 g (molar mass=60 g mol^(-1)) per litre of solution water has the same osmotic pressure (isotonic ) as a solution of glucose (molar mass =180g mol^(-1)) in water calculate the mass of glucose present in one litre of its solution.

A solution containing 15 g of urea (Molar mass =60 g mol^(-1) ) per litrea has the same osmotic presure (isotonic) as a solution of glucose (molar mass =180 g mol^(-1) ) in water, Calculate themass of glucose present in one litre of the solution.

Knowledge Check

  • 36g of glucose (molar mass = 180 g//mol) is present in 500g of water, the molarity of the solution is

    A
    0.2
    B
    `0.4`
    C
    0.8
    D
    `1`

  • What is the molality of a solution containing 200 mg of urea (molar mass = 60 g mol^(-1) ) ?

    A
    0.0825
    B
    0.825
    C
    0.498
    D
    0.0014

  • What is the molarity of a solution containting 200 mg of urea ( molar mass : 60 g mol ^(-1) ) dissolved in 500 g of water ?

    A
    `0.08325 m`
    B
    `2 c c`
    C
    `2.15 c c`
    D
    `2.30 c c`

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    If 1.8 g of glucose (molar mass = 180) is dissolved in 60 g of water the mole fraction of glucose is

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    If 3g of glucose (molecular mass 180) is dissolved in 60g of water at 15^(@)C , then the osmotic pressure of this solution will be :

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