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Calculate the freezing point depression ...

Calculate the freezing point depression expected for `0.0711` m aqueous solution of `Na_(2)SO_(4)` . If this solution actually freezes at `-0.320 ^(@)C` , what would be the value of Van't Hoff factor ?
(`K_(f)` for water is `1.86 ^(@)C mol^(-1)`) .

Text Solution

Verified by Experts

Freezing point depression.
`Delta T_(f) = k_(f) xx m`
`k_(f) = 1.86^(@)C , mol^(-1) , m = 0.0711`
`Delta T_(f) = 1.86 xx 0.0711 = 0 .132^(@)`
Observed freezing point ` = 0- (-0.320) = 0.320^(@)`
Van.t Hoff factor `= ("Observed freezing point")/("Calculated freezing point")`
` = (0.320)/(0.132)`
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