How many grams of wet NaOH contianing 15% water is required to prepare 6L of 0.5 M NaOH solution?

Explanation

To find out how many grams of wet NaOH containing 15% water is required to prepare 6L of a 0.5 M NaOH solution, we can follow these steps:

### Step 1: Calculate the number of moles of NaOH required
The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. Therefore, to find the total moles of NaOH needed for 6L of a 0.5 M solution:

\[ \text{Moles of NaOH} = \text{Molarity} \times \text{Volume (L)} = 0.5 \, \text{mol/L} \times 6 \, \text{L} = 3 \, \text{moles} \]
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