When a gas is bubbled through water at 298 K, a very dilute solution of gas is obtained . Henry's law constant for the gas is 100 kbar. If gas exerts a pressure of 1 bar, the number of moles of gas dissolved in 1 litre of water is

Options

A. 0.555
B. 5.55
C. 0.0555
D. 55.5

Answer

A

Explanation

The mole fraction of the gas in the solution ,
`x = (p)/(K_(H)) = (1)/(1000 xx 10^(3)) = 10^(-5) bar`
If n is the number of mole of gas in a solution of 1 L of water contain 55.5 mol , then .
` x = (n)/(n+55.5) = (n)/(55.5) ~~ 1.00 xx 10^(-5)`
`therefore " " n = 55.5 xx 10^(-5)` millimoles.
or`" " = 0.55` millimoles .