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The vapour pressure of two pure isomeric...

The vapour pressure of two pure isomeric liquids X and Y are 200 torr and 100 torr respectively at a given temperature. Assuming a solution of these components to obey Raoults law, the mole fraction of component X in vapour phase in equilibrium with the solution containing equal amounts of X and Y, at the same temperature is :

A

0.22

B

5.55

C

0.0555

D

55.5

Text Solution

Verified by Experts

The correct Answer is:
D

For equimolar solution of X and Y.
` x_(x) = 0.5, x_(y) = 0.5`
`p_(X) = 0.5 xx 200 = 100 torr`
`p_(y) = 0.5 xx 100 = 50 torr`
`p_("tota") = 100 + 50 + 150 torr`
Mole fraction of component X in vapour phase, `y_(x) = (100)/(150) =0.67`
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