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6.02xx10^(20) molecules of urea are pres...

`6.02xx10^(20)` molecules of urea are present in 100 ml of its solution. The concentration of solution is :

A

`0.001M`

B

`0.1M`

C

`0.02M`

D

`0.01M`

Text Solution

Verified by Experts

The correct Answer is:
D

Moles of urea ` = (6.02 xx 10^(20))/(6.02 xx 10^(23)) = 1 xx 10^(-3)`
Molarity `= (1 xx 10^(-3))/(100)xx 1000 = 0.01 M`
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