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Freezing point of an aqueous solution is...

Freezing point of an aqueous solution is `-0.186^(@)C`. Elevation of boiling point of the same solution is ……..if `K_(b)=0.512 K "molality"^(-1)`and `K_(f)=1.86K "molality"^(-1)` :

A

0.52

B

1.04

C

1.34

D

`0.134`

Text Solution

Verified by Experts

`(Delta T_(f))/(Delta T_(b)) = (K_(f))/(k_(b))`
`Delta T_(f) = 0 -(-0.186) = 0.186^(@)C`
`(0.186)/(Delta T_(b)) = (1.86)/(0.52) = 0.052`
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MODERN PUBLICATION-SOLUTIONS-COMPETITION FILE (B. MULTIPLE CHOICE QUESTIONS(MCQ))
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