`18 g` of glucose `(C_(6)H_(12)O_(6))` is dissolved in `1 kg` of water in a saucepan. At what temperature will the water boil (at 1 atm) ? `K_(b)` for water is `0.52 K kg mol^(-1)`.

Options

A. 373.15K
B. 373.67K
C. 374.19 K
D. 373.10K

Answer

C

Explanation

Molality of NaCl solution = 1m
`i=2` for NaCl .
`Delta T_(b) = I K_(b) m = 2 xx 0.52 xx 1 = 1.04`
Boiling point of solution ` =373.15+1.04 = 374.19K`