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A solution is prepared by dissolving 0.6...

A solution is prepared by dissolving 0.6 g of urea (molar mass `=60 g"mol"^(-1)`) and 1.8 g of glucose (molar mass `=180g"mol"^(-1)`) in 100 mL of water at `27^(@)C`. The osmotic pressure of the solution is:
`(R=0.8206L "atm"K^(-1)"mol"^(-1))`

A

4.92 atm

B

1.64 atm

C

2.46 atm

D

8.2 atm

Text Solution

Verified by Experts

The correct Answer is:
A
`pi = (((0.6)/(60) + (1.8)/(180)))/(0.1) xx 0.082 xx 300`
` = 4.29 atm`
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