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A solution of sucrose (molar mass = 342 ...

A solution of sucrose (molar mass `= 342 "g mol"^(-1)`) has been prepared by dissolving 68.5g of sucrose in 1000g of water. The freezing point of the solution obtained will be :
(`K_(f)` for water `= 1.86 "K kg mol"^(-1)`)

A

`0.0220` atm

B

0.238 atm

C

0.0238 atm

D

0.220 atm

Text Solution

Verified by Experts

The correct Answer is:
C
`(p_(A)^(@) - p_(A))/(p_(A)^(@)) = (w_(B)//M_(B))/(w_(A)//M_(A))`
` (0.024 -p_(A))/(0.024) = (7.2//180)/(100//18)`
` 0.024 -p_(A) = 0.024 (0.0072) = 0.0001728`
`therefore " "p_(A) = 0.024 - 0.0001728 = 0.0238 atm`
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