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A 0.2 molal aqueous solution of weak aci...

A 0.2 molal aqueous solution of weak acid (HX) is 20% ionised. The freezing point of this solution is (Given, `K_(f) = 1.86^(@) C m^(-1)` for water)

A

`101.04^(@)C`

B

`100.104^(@)C`

C

`100.1248^(@)C`

D

`100.52^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
`underset("m(1-0.20))(HX (aq)) to underset(m(0.20))(H^(+)) + underset(m(0.20))(X^(-))`
Molal conc. Of soln = `m (1-0.20) + 0.20 m + 0.20 m`
` = 1.20 m`
`Delta T_(b) = K_(b) xx m`
` = 0.52 xx 1.20 (0.2) = 0.1248`
Boiling point `= 100.1248^(@)C`
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