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Calculate the resistance of 0.01 N solut...

Calculate the resistance of 0.01 N solution of an electrolyte whose equivalent conductivity is 420 `ohm^(-1) cm^(2) equiv^(-1)`. (The cell constant of the cell is 0.88 `cm^(-1)` )

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To calculate the resistance of a 0.01 N solution of an electrolyte with an equivalent conductivity of 420 ohm^(-1) cm^(2) equiv^(-1) and a cell constant of 0.88 cm^(-1), we can follow these steps: ### Step 1: Understand the relationship between equivalent conductivity (λ), conductivity (κ), and concentration (C). The formula for equivalent conductivity is given by: \[ \lambda = \frac{\kappa \times 1000}{C} \] where: - \( \lambda \) = equivalent conductivity (ohm^(-1) cm^2 equiv^(-1)) - \( \kappa \) = conductivity (ohm^(-1) cm^(-1)) - \( C \) = concentration (equivalents per liter) ### Step 2: Rearrange the formula to find conductivity (κ). From the above equation, we can rearrange it to find conductivity: \[ \kappa = \frac{\lambda \times C}{1000} \] ### Step 3: Substitute the known values into the equation. Given: - \( \lambda = 420 \, \text{ohm}^{-1} \text{cm}^2 \text{equiv}^{-1} \) - \( C = 0.01 \, \text{N} \) (which is equivalent to 0.01 equivalents per liter) Substituting the values: \[ \kappa = \frac{420 \times 0.01}{1000} = \frac{4.2}{1000} = 4.2 \times 10^{-3} \, \text{ohm}^{-1} \text{cm}^{-1} \] ### Step 4: Use the relationship between conductivity, resistance (R), and cell constant (X). The relationship is given by: \[ \kappa = \frac{1}{R} \times X \] where: - \( R \) = resistance (ohms) - \( X \) = cell constant (cm^(-1)) ### Step 5: Rearrange the formula to find resistance (R). Rearranging the equation gives: \[ R = \frac{X}{\kappa} \] ### Step 6: Substitute the known values into the equation. Given: - \( X = 0.88 \, \text{cm}^{-1} \) - \( \kappa = 4.2 \times 10^{-3} \, \text{ohm}^{-1} \text{cm}^{-1} \) Substituting the values: \[ R = \frac{0.88}{4.2 \times 10^{-3}} = \frac{0.88}{0.0042} \approx 209.52 \, \text{ohms} \] ### Conclusion: The resistance of the 0.01 N solution of the electrolyte is approximately **209.52 ohms**. ---

To calculate the resistance of a 0.01 N solution of an electrolyte with an equivalent conductivity of 420 ohm^(-1) cm^(2) equiv^(-1) and a cell constant of 0.88 cm^(-1), we can follow these steps: ### Step 1: Understand the relationship between equivalent conductivity (λ), conductivity (κ), and concentration (C). The formula for equivalent conductivity is given by: \[ \lambda = \frac{\kappa \times 1000}{C} \] where: ...
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