The `Lambda^(@)` values of `KNO_3` and `LiNO_3` are 145.0 and 110.1 ` S cm^(2) mol^(-1)` respectively . The `lambda^(@)` value for `K^(+)` ion is `73.5 S cm^(2) mol^(-1)` . Calculate `lambda^(@) (Li^(+))` .

Answer

`38.6 S cm^(2) mol^(-1)`

Explanation

`lambda_(m)^(oo) (NO_(3)^(-)) = Lambda^(oo) (KNO_(3)) - lambda^(oo) (K^(+))`
`= 145.0 - 73.5 = 71.5 S cm^(2) mol^(-1)`
`lambda^(oo) (Li^(+)) = Lambda^(oo) (LiNO_(3)) - lambda^(oo) (NO_(3)^(-))`
`= 110.1 - 71.5 = 38.6 S cm^(2) mol^(-1)`