Molar conductivities at infinite dilution (at 298 K) of `NH_(4)CI`, NaOH and NaCI are 129.8, 217.4 and 108.9 `Omega^(-1)cm^(2)mol^(-1)` respcetively. If the molar conductivity of a centimolar solution of `NH_(4)OH` is 9.33 `Omega^(-1) cm^(2)mol^(-1)`, what is percentage dissociation of `NH_(4)OH` at this concentation ? Also calculte the dissociation constant for `NH_(4)OH`.

Answer

0.039

Explanation

`Lambda^(oo) (NH_(4)OH) = Lambda^(oo) (NH_(4)Cl) + Lambda^(oo) (NaOH) - Lambda^(oo) (NaCl)`
`= 239.2 ohm^(-1) cm^(2) mol^(-1)`