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Calculate the standard reduction potenti...

Calculate the standard reduction potentials of galvanic cells in which reaction are
`Fe^(2+) (aq) + Ag^(+) (aq) to Fe^(3+) (aq) + Ag (s)`
Given that `E^(Theta) (Cr^(3+) //Cr) = -0.74 V , E^(Theta) (Cd^(2+) // Cd) = -0.40 V ` , `E^(Theta) (Fe^(3+) // Fe^(2+)) = 0.77 V , E^(Theta) (Ag^(+) // Ag) = 0.80 V `

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To calculate the standard reduction potentials for the given galvanic cell reaction: **Reaction:** \[ \text{Fe}^{2+} (aq) + \text{Ag}^{+} (aq) \rightarrow \text{Fe}^{3+} (aq) + \text{Ag} (s) \] **Step 1: Identify the oxidation and reduction half-reactions.** - **Oxidation:** The iron ion \(\text{Fe}^{2+}\) is oxidized to \(\text{Fe}^{3+}\). - **Reduction:** The silver ion \(\text{Ag}^{+}\) is reduced to silver metal \(\text{Ag}\). **Step 2: Write the half-reactions.** - Oxidation half-reaction: \[ \text{Fe}^{2+} \rightarrow \text{Fe}^{3+} + e^{-} \] - Reduction half-reaction: \[ \text{Ag}^{+} + e^{-} \rightarrow \text{Ag} \] **Step 3: Find the standard reduction potentials for each half-reaction.** - Given: - \(E^{\Theta}(\text{Fe}^{3+}/\text{Fe}^{2+}) = 0.77 \, \text{V}\) - \(E^{\Theta}(\text{Ag}^{+}/\text{Ag}) = 0.80 \, \text{V}\) **Step 4: Convert the reduction potential of the oxidation half-reaction.** - The oxidation potential for \(\text{Fe}^{2+} \rightarrow \text{Fe}^{3+}\) is the negative of the reduction potential: \[ E^{\Theta}(\text{Fe}^{2+}/\text{Fe}^{3+}) = -E^{\Theta}(\text{Fe}^{3+}/\text{Fe}^{2+}) = -0.77 \, \text{V} \] **Step 5: Calculate the standard cell potential \(E^{\Theta}_{cell}\).** - The overall cell potential is calculated by adding the oxidation potential of iron and the reduction potential of silver: \[ E^{\Theta}_{cell} = E^{\Theta}(\text{Ag}^{+}/\text{Ag}) + E^{\Theta}(\text{Fe}^{2+}/\text{Fe}^{3+}) \] \[ E^{\Theta}_{cell} = 0.80 \, \text{V} + (-0.77 \, \text{V}) \] \[ E^{\Theta}_{cell} = 0.80 \, \text{V} - 0.77 \, \text{V} \] \[ E^{\Theta}_{cell} = 0.03 \, \text{V} \] **Final Answer:** The standard cell potential \(E^{\Theta}_{cell}\) for the reaction is \(0.03 \, \text{V}\). ---

To calculate the standard reduction potentials for the given galvanic cell reaction: **Reaction:** \[ \text{Fe}^{2+} (aq) + \text{Ag}^{+} (aq) \rightarrow \text{Fe}^{3+} (aq) + \text{Ag} (s) \] **Step 1: Identify the oxidation and reduction half-reactions.** - **Oxidation:** The iron ion \(\text{Fe}^{2+}\) is oxidized to \(\text{Fe}^{3+}\). - **Reduction:** The silver ion \(\text{Ag}^{+}\) is reduced to silver metal \(\text{Ag}\). ...
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