A copper wire is dipped in silver nitrate solution in beaker A and a silver wire is dipped in a solution of copper sulphate kept in a beaker B . If the standard electrode potential for
`Cu^(2+) + 2e^(-) to Cu` is +0.34 for `Ag^(+) + e^(-) to Ag` is 0.80 V
Predict in which beaker the ions present will get reduced ?

Explanation

To solve the problem, we need to analyze the two beakers and the reactions that take place in each when the respective wires are dipped in the solutions.

### Step-by-Step Solution:

1. **Identify the Solutions and Wires:**
- Beaker A contains silver nitrate (AgNO₃) solution with a copper wire.
- Beaker B contains copper sulfate (CuSO₄) solution with a silver wire.

2. **Standard Electrode Potentials:**
- For the reduction half-reaction of copper:
\[ \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \quad E^\circ = +0.34 \, \text{V} \]
- For the reduction half-reaction of silver:
\[ \text{Ag}^+ + e^- \rightarrow \text{Ag} \quad E^\circ = +0.80 \, \text{V} \]

3. **Determine the Tendency of Reduction:**
- A higher standard electrode potential indicates a greater tendency for the species to be reduced.
- Comparing the two potentials:
- Silver (Ag) has a higher potential (+0.80 V) than copper (+0.34 V).
- Therefore, Ag⁺ ions will have a stronger tendency to be reduced compared to Cu²⁺ ions.

4. **Reactions in Each Beaker:**
- **In Beaker A (Cu wire in AgNO₃):**
- The reaction involves the reduction of Ag⁺ ions:
\[ \text{Ag}^+ + e^- \rightarrow \text{Ag} \quad (\text{Ag is reduced}) \]
- Copper wire does not get oxidized because Ag⁺ has a higher tendency to be reduced.

- **In Beaker B (Ag wire in CuSO₄):**
- The reaction involves the oxidation of Ag:
\[ \text{Ag} \rightarrow \text{Ag}^+ + e^- \quad (\text{Ag is oxidized}) \]
- Cu²⁺ ions do not get reduced because Ag wire will lose electrons instead.

5. **Conclusion:**
- The ions present in Beaker A (Ag⁺) will get reduced to Ag.
- The ions present in Beaker B (Cu²⁺) will not be reduced; instead, Ag will be oxidized.

### Final Answer:
The ions present in Beaker A will get reduced.