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(a) Define the following terms : (i) L...

(a) Define the following terms :
(i) Limiting molar conductivity,
(ii) Fuel cell
(b) Resistance of a conductivity cell filled with `0.1 molL^(-1)KCl` solution is 100 W. If the resistance of the same cell when filled with `0.2 mol L^(-1)KCl` solution is 520 W , calculate the conductivity and molar conductivity of `0.2 mol L^(-1) KCl` solution. The conductivity of `0.1 mol L^(-1) KCl` solution is ` 1.29xx10^(-1) W^(-1) cm^(-1)` .

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1 mol of KCl in 500 cc
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(a) Define the following terms : (i) Limiting molar conductivity, (ii) Fuel cell (b) Resistance of a conductivity cell filled with 0.1 molL^(-1)KCl solution is 100 Ohm. If the resistance of the same cell when filled with 0.2 mol L^(-1)KCl solution is 520 Ohm , calculate the conductivity and molar conductivity of 0.2 mol L^(-1) KCl solution. The conductivity of 0.1 mol L^(-1) KCl solution is 1.29xx10^(-1) Scm^(-1) .

The resistance of a conductivity cell filled with 0.1 M KCl solution is 100 Omega . If R of the same cell when filled with 0.02 M KCl solution is 520 Omega , calculate the conductivity and molar conductivity of 0.02 M KCl solution. The conductivity of 0.1 M KCl solution is 1.29 S m^(-1) .

Resistance of a conductivity cell filled with 0.1 M KCl is 100 ohm. If the resistence of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. Conductivity of 0.1 KCl solution is 1.29xx10^(-2)" ohm "^(-1)cm^(-1) .

Calculating conductivity and molar conductivity: Resistance of a conductivity cell filled with 0.1 M KCl solution is 100 Omega . If the resistance of the same cell when filled with 0.02 M KCl solutions 520 Omega and the conductivity of 0.1 KCl solution is 1.29 S m , calculate the conductivity and moalr conductivity of 0.02 M KCl solution. Strategy : Calculate the cell constant with the help of 0.01 M KCl solution (both R and kappa are Known). Use the cell constant to determine the conductivity of 0.02 M KCl solution and finally find its molar conductivity using the molarity

The conductivity of 0.1 m KCl solution is 1.29sm^(-1) . If the resistance of the cell filled with 0.1 M KCl is 100 ohm. Calculate the cell constant.

Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100Omega . is 1.29 S m^(-1) . Resistance of the same cell when filled with 0.2 M of the same solution is 520Omega . The The molar conductivity of 0.2 M solution of the electrolyte will be :

When a certain conductance cell was finlled with 0.1 mol L^(-1) KCI solution, it had a resistance of 85 ohm at 298K. When the same cell was filled with an aqueous solution of 0.052 mol L^(-1) of an electrolyte, the resistance was 96 ohm. Calcualte the molar conductance of the electrolyte at this concentration. (Specific conductance of 0.1 mol L^(-1) KCI solution is 1.29xx10^(-2)ohm^(-1)cm^(-1)) .

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