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Calculate limiting molar conductivity of `CaSO_(4)` given that limiting molar conductivity of calcium and sulphate ions are 119.0 and `160.0" S "cm^(2) mol^(-1)` respectively.

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`Lambda_(m)^(@) (CaSO_(4)) = lambda_(m)^(@) (Ca^(2+)) + lambda_(m)^(@) (SO_(4)^(2-))`
`= 119.0 + 106.0`
`= 225.0 S cm^(2) mol^(-1)`.
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